JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1

f:R \to S

, defined by

f\left( x \right) = \sin x - \sqrt 3 \cos x - 1

is onto, then the intervel of s is

View answer and explanation

Correct option: D

\left[ { - 1,\mathrm{ }3} \right]

Option D is correct because the range of sin(x) - sqrt(3)cos(x) - 1 is [-1, 3] when the function is onto.

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S=\left\{x: f(x)=f^{-1}(x)\right\}