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JEE PHYSICS MCQ: WORK-ENERGY-POWER

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A person stands on a spring balance at the equator. By what percentage is the balance reading less than his true weight?
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Correct option: A
0.35%0.35 \%
Option A (0.350.35 \\%) is correct because the percentage difference is calculated using the formula (ω2R/g\omega^2 R / g) * 100, accounting for the Earth's rotation.

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