JEE PHYSICS MCQ: THERMODYNAMICS

1 Hard

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Application +4 | -1

A diatomic gas

(\gamma=1.4)

does

100 \mathrm{~J}

of work in an isobaric expansion. The heat given to the gas is:

View answer and explanation

Correct option: A

350 \mathrm{~J}

Option A (

350 \mathrm{~J}

) is correct because for an isobaric process, the heat given to the gas is calculated using

Q = \Delta U + W

, where

\Delta U = \frac{f}{2} nR \Delta T

and

W = nR \Delta T

. For a diatomic gas,

f = 5

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