JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1

a f(x+1)+b f\left(\frac{1}{x+1}\right)=x, x \neq-1, a \neq b

, then

f(2)

is equal to:

View answer and explanation

Correct option: A

\frac{2 a+b}{2\left(a^2-b^2\right)}

Option A (

\frac{{2a+b}}{{2(a^2-b^2)}}

) is correct because it is the value of f(2) obtained by solving the system of equations formed by substituting x=1 and x=-1/2 into the given functional equation.

More Questions from FUNCTIONS

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

, where

f(x)=x(4-x)

, then

f^{-1}(x)

is given by: If

g(f(x))=|\sin x|

and

f(g(x))=(\sin \sqrt{x})^2

, then Let

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

be defined by

f\left( x \right) = x - \left[ x \right]

, then

{f^{ - 1}}\left( x \right)

equals Let

f: R \rightarrow R

be defined as

f(x)=x^4

, Choose the correct answer. Which of the following functions are odd functions Let

f(x)=(x+1)^2-1(x \geq-1)

. Then the set

S=\left\{x: f(x)=f^{-1}(x)\right\}

contains