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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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∫11−e2xdx=\int \frac{1}{\sqrt{1-e^{2 x}}} d x=
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Correct option: A
x−log⁡[1+1−e2x]+cx-\log \left[1+\sqrt{1-e^{2 x}}\right]+c
Option A is correct because the integral can be solved by rewriting the integrand and using substitution, leading to the expression x−log⁡[1+1−e2x]+cx - \log[1 + \sqrt{1 - e^{2x}}]+c.

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