JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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Application +4 | -1

Find the angular velocity of a body rotating with an acceleration of

2 \mathrm{~rev} / \mathrm{s}^2

as it completes the 5th revolution after the start.

View answer and explanation

Correct option: A

2 \sqrt{5} \mathrm{~rev} / \mathrm{s}

Option C (

n p

) is correct because the bulk modulus is derived from the given process equation

TV^{n-1} = constant

and the definition of bulk modulus.

More Questions from SYSTEM OF PARTICLES

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\mathrm{AB}

\mathrm{L}

\mu(x)=a+\frac{b x}{L}

x

\mathrm{A}

\mathrm{CM}

\left(\frac{7}{12}\right) \mathrm{L}

\mathrm{A}

\mathrm{b}

1.0 \mathrm{~g}

8 \mathrm{~cm}

\omega = {t^4} + 2{t^3}

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)