JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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If a ball of

70 \mathrm{~kg}

mass hits an ice cube and temperature of ball is

100^{\circ} \mathrm{C}

, then how much ice converted into water? (Specific heat of ball is

0.2 \mathrm{~cal} \mathrm{~g}^{-1}

, Latent heat of ice

=80 \mathrm{~cal} \mathrm{~g}^{-1}

)

View answer and explanation

Correct option: C

1.75 \times 10^4 \mathrm{~g}

Option C (

1.75 \times 10^4 \mathrm{~g}

) is correct because it is the amount of ice converted into water, calculated using the heat lost by the ball and the latent heat of fusion of ice.

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