JEE MATHEMATICS MCQ: MAXIMA & MINIMA

1 Easy

1 of 1

Analyzing +4 | -1

P(x)

is polynomial satisfying

P\left(x^2\right)=x^2 P(x)

and

P(0)=-2, P^{\prime}(3 / 2)=0

and

P(1)=0

.
The maximum value of

P(x)

View answer and explanation

Correct option: B

-\frac{1}{4}

Option B (

-\frac{1}{4}

) is correct. By using the given conditions to determine the polynomial

P(x)

, we find its maximum value to be

-\frac{1}{4}

More Questions from MAXIMA & MINIMA

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f(x)=\left(1+b^2\right) x^2+2 b x+1

m(b)

f(x)

b

m(b)

f: R \rightarrow R

f(x)=(x-3)^{n_1}(x-5)^{n_2}, n_1, n_2 \in N

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x<0

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p

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\left[ {1/\sqrt 3 ,\;\sqrt 3 } \right]

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\frac{k}{e}

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