Question

$\smallint \,\,\frac{{{x^3}\,\,\sin \,\,\left[ {{{	an }^{ - 1}}\,\,\left( {{x^4}} ight)} ight]}}{{1\,\, + \,\,{x^8}}}\,\,dx$ is equal to

Accepted Answer

$ - \frac{1}{4}\,\,\cos \,\,\left[ {{{	an }^{ - 1}}\,\,\left( {{x^4}} ight)} ight]\,\, + \,\,c$

Answer

$\frac{1}{4}\,\,\cos \,\,\left[ {{{	an }^{ - 1}}\,\,\left( {{x^4}} ight)} ight]\,\, + \,\,c$

Answer

$\frac{1}{4}\,\,\sin \,\,\left[ {{{	an }^{ - 1}}\,\,\left( {{x^4}} ight)} ight]\,\, + \,\,c$

Answer

$\frac{1}{4}\,\,{\sec ^{ - 1}}\,\,\left[ {{{	an }^{ - 1}}\,\,\left( {{x^4}} ight)} ight]\,\, + \,\,c$

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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