JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

Option D ($d_{xy}, d_{xz}, d_{yz}$) is correct because the hybridization of the central atom in $\mathrm{ICl}_4^{-}$ is $sp^3d^2$, which involves $d_{z^2}$ and $d_{x^2-y^2}$ orbitals, but not $d_{xy}, d_{xz}, d_{yz}$ orbitals.