Back to CHEMICAL BONDING & MOLECULAR STRUCTURE

JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

1 Medium

1 of 1

Understanding +4 | -1

Which of the following gives correct arrangement of compounds involved based on their bond strength

View answer and explanation

Correct option: A

{HF}>{HCl}>{HBr}>{HI}

Option A (

{HF}>{HCl}>{HBr}>{HI}

) is correct because bond strength decreases as the size of the halogen increases, with HF having the strongest bond due to fluorine's small size and high electronegativity.

More Questions from CHEMICAL BONDING & MOLECULAR STRUCTURE

Practice All Chapter MCQs →

The hybridization in sulphur dioxide is

\mathrm{C}{\mathrm{O}_2}

has the same geometry as:

\left( A \right)\mathrm{HgC}{\mathrm{l}_2},\left( B \right)\mathrm{N}{\mathrm{O}_2},\left( C \right)\mathrm{SnC}{\mathrm{l}_4},\left( D \right){\mathrm{C}_2}{\mathrm{H}_2}

The pair of molecules forming strongest hydrogen bonds are Paramagnetism is shown by Which statement is correct? Assertion (A) :

{BF}_3

is a weaker Lewis acid than

{BCl}_3

.

Reason (R) : The planar

{BF}_3

molecule is stabilised to a greater extent than

{BCl}_3

{B}-X \pi

-bonding.