If $y = 4x - 5$ is a tangent to the curve ${y^2} = p{x^3} + q$ at (2, 3) then

JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Easy

1 of 1

Application +4 | -1

y = 4x - 5

is a tangent to the curve

{y^2} = p{x^3} + q

at (2, 3) then

View answer and explanation

Correct option: A

p = 2,\;q = - 7

Option A (

p = 2,\;q = - 7

) is correct because these values of p and q satisfy both the equation of the curve at the given point and the slope of the tangent at that point.

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a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z