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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1
If ∫1+x3x2/3 dx=2f(x)3/2+C\int \frac{\sqrt{1+\sqrt[3]{x}}}{x^{2 / 3}} \mathrm{~d} x=2 f(x)^{3 / 2}+C then f(x)f(x) is equal to
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Correct option: B
1+x1/31+x^{1 / 3}
Option B (1+x1/31+x^{1 / 3}) is correct because after substituting t2=1+x1/3t^2 = 1 + x^{1/3}, the integral simplifies to 2(1+x1/3)3/2+C2(1+x^{1/3})^{3/2} + C, matching the given form.

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