The coordination number of $Cr$ in $\left[ {{\rm{Cr}}{{\left( {{\rm{N}}{{\rm{H}}_3}} \right)}_3}{{\left( {{{\rm{H}}_2}{\rm{O}}} \right)}_3}} \right]{\rm{C}}{{\rm{l}}_3}\,{\rm{is}}:$

NEET UG CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

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The coordination number of

Cr

\left[ {\mathrm{Cr}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_3}{{\left( {{\mathrm{H}_2}\mathrm{O}} \right)}_3}} \right]\mathrm{C}{\mathrm{l}_3}\,\mathrm{is}:

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Correct option: C

Option C (6) is correct because the coordination number is the number of ligands directly attached to the central metal ion, which in this case is 3 NH3 and 3 H2O, totaling 6.

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The complexes

\left[ {\mathrm{PtC}{\mathrm{l}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{B}{\mathrm{r}_2}\mathrm{\;and\;}\left[ {\mathrm{PtB}{\mathrm{r}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{C}{\mathrm{l}_2}\mathrm{\;}

are example for isomerism The total number of stereoisomers for the complex

\left[\mathrm{Cr}(\mathrm{Ox})_{2} \mathrm{ClBr}\right]^{3-}

(where

\text{ox =}

oxalate) is The value of

x

on the

{\left[ {\mathrm{Ni}{{\left( {\mathrm{CN}} \right)}_4}} \right]^x}

is: Excited state configuration of

\mathrm{M}{\mathrm{n}^{2 + }}

\mathrm{CuS}{\mathrm{O}_4}

decolourises on addition of KCN, the product is: The IUPAC name of

{\mathrm{K}_2}\left[ {\mathrm{Ni}{{\left( {\mathrm{CN}} \right)}_4}} \right]