Skip to main content
Back to MEAN VALUES THEOREM

JEE MATHEMATICS MCQ: MEAN VALUES THEOREM

1 Easy
1 of 1
Understanding +4 | -1
Let SS be the set of all functions f:[0, 1]→R,f:\left[ {0,\,1} \right] \to R, which are continuous on [0,1] and differentiable on (0,1). Then for every ff in SS, there exists a c ∈(0,1),c\, \in (0,1), depending on ff, such that
View answer and explanation
Correct option: A
f(1)−f(c)1−c=f′(c′)\frac{{f(1) - f(c)}}{{1 - c}} = f'(c')
Option A (f(1)−f(c)1−c=f′(c′)\frac{{f(1) - f(c)}}{{1 - c}} = f'(c')) is correct because it directly applies the Mean Value Theorem (MVT) or Lagrange's Mean Value Theorem (LMVT).

More Questions from MEAN VALUES THEOREM

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.