JEE PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1

1\,m{m^3}

of a gas is compressed at '

1

' atmospheric pressure and temperature

{27^0}C\,to\,{627^0}C

. What is the final pressure under adiabatic condition

\left( {\gamma for\,the\,gas = 1.5} \right)

View answer and explanation

Correct option: A

27 \times {10^5}N/{M^2}

Option A (

27 \times {10^5}N/{M^2}

) is correct because it follows from the adiabatic condition equation relating pressure and temperature.

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0.25\,\,{m^3}

{10^3}N/{m^2},

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\left( {\gamma = \frac{{{C_p}}}{{{C_v}}}} \right)