JEE CHEMISTRY MCQ: P-BLOCK ELEMENTS

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Assertion (A) : Anhydrous

\mathrm{H}_2 \mathrm{SO}_4

undergoes autoprotolysis

\mathrm{H}_2 \mathrm{SO}_4+\mathrm{H}_2 \mathrm{SO}_4 \rightleftharpoons \mathrm{H}_3 \mathrm{SO}_4^{+}+\mathrm{HSO}_4^{-}

Reason (R) : Anhydrous

\mathrm{H}_2 \mathrm{SO}_4

has very high electrical conductivity.

View answer and explanation

Correct option: B

Both

\mathbf{A}

and

\mathbf{R}

are true but

\mathbf{R}

is not the correct explanation of

\mathbf{A}

Option B (Both

\mathbf{A}

and

\mathbf{R}

are true but

\mathbf{R}

is not the correct explanation of

\mathbf{A}

.) is correct because anhydrous

\mathrm{H}_2 \mathrm{SO}_4

does undergo autoprotolysis, and it has high electrical conductivity, but the conductivity is not the direct reason for autoprotolysis.

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17^{\text {th }}

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{O}_2

\mathrm{C}{\mathrm{N}^ - }

{\mathrm{N}_2}

\mathrm{C}{\mathrm{N}^ - },\mathrm{\;}{\mathrm{N}_2}

2 {Fe}^{3+}+{SO}_2+2 {H}_2 {O} \rightarrow 2 {Fe}^{2+}+{SO}_4^{2-}+4 {H}^{+}

{H}_2 {~S}_2 {O}_8

{S}={O}

{S}-{OH}

{O}-

{O}

{NH}_3

{H}_2 {SO}_4

{H}_2 {SO}_4