For the reaction $3{{\rm{O}}_2} \to 2{{\rm{O}}_3}$;∆H=+ve, we can say :

${{\rm{O}}_3}$is less stable than${{\rm{O}}_2}$

${{\rm{O}}_3}$is more stable than ${{\rm{O}}_2}$

Formation of${{\rm{O}}_3}$ is exothermic

NEET UG CHEMISTRY MCQ: THERMODYNAMICS

1 Easy

1 of 1

Understanding +4 | -1

For the reaction

3{\mathrm{O}_2} \to 2{\mathrm{O}_3}

;∆H=+ve, we can say :

View answer and explanation

Correct option: B

{\mathrm{O}_3}

is less stable than

{\mathrm{O}_2}

Option B (

{\mathrm{O}_3}

is less stable than

{\mathrm{O}_2}

) is correct because the positive ∆H indicates that energy is absorbed to form O3, making it less stable than O2.

Practice All Chapter MCQs →

{T_i}

{T_f}

\mathrm{H}_2 \mathrm{O}(\mathrm{s}) \rightarrow \mathrm{H}_2 \mathrm{O}(\mathrm{g})

\mathrm{X}_2 \mathrm{O_4(l}) \longrightarrow 2 \mathrm{XO}_2(\mathrm{g}), \Delta U=2.1 \mathrm{~kcal}, \Delta S=20 \mathrm{~cal} \mathrm{~K}^{-1}

300 \mathrm{~K}

\Delta G