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NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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Application +4 | -1
For the reaction, X2O4(l)⟶2XO2(g),ΔU=2.1 kcal,ΔS=20 cal K−1\mathrm{X}_2 \mathrm{O_4(l}) \longrightarrow 2 \mathrm{XO}_2(\mathrm{g}), \Delta U=2.1 \mathrm{~kcal}, \Delta S=20 \mathrm{~cal} \mathrm{~K}^{-1} at 300 K300 \mathrm{~K}. Hence, ΔG\Delta G is
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Correct option: B
−2.7 kcal-2.7 \mathrm{~kcal}
Option B (-2.7 kcal) is correct because it is calculated using the formula ΔG=ΔH−TΔS\Delta G = \Delta H - T\Delta S, where ΔH\Delta H is derived from ΔU\Delta U and the change in the number of moles of gas.

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