JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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\int \,\,\frac{{{{\left( {{{\tan }^{ - 1}}\,\,x} \right)}^3}}}{{\left( {1\,\, + \,\,{x^2}} \right)}}\,\,dx

is equal to

View answer and explanation

Correct option: B

\frac{{{{\left( {{{\tan }^{ - 1}}x} \right)}^4}}}{4}\,\, + \,\,c

Option B ((((tan^-1x)⁴)/4) + c) is correct because it is the result of a straightforward u-substitution where u = tan^-1x.

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