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NEET UG PHYSICS MCQ: ALTERNATING CURRENT

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Analyzing +4 | -1
A series L−C−RL-C-R circuit is connected to an AC\mathrm{AC} voltage source. When LL is removed from the circuit, the phase difference between current and voltage is π4\frac{\pi}{4}. If instead CC is removed from the circuit, the phase difference is again π4\frac{\pi}{4} between current and voltage. The power factor of the circuit is
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Correct option: B
1
Option B (1) is correct because when L and C are removed individually and the phase difference is π4\frac{\pi}{4}, it implies that the circuit is at resonance, making the power factor equal to 1.

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