JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1

1, \omega

and

\omega^2

are the three cube roots of unity, then

(1+\omega)\left(1+\omega^2\right)\left(1+\omega^4\right)\left(1+\omega^8\right) \ldots

2 n

factors is equal to

View answer and explanation

Correct option: A

Option A (1) is correct because the product simplifies to 1 using the properties of complex cube roots of unity.

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