In ${\rm{Cr}}{\left( {{\rm{N}}{{\rm{H}}_3}} \right)_4}{\rm{C}}{{\rm{l}}_2}]{\rm{Cl}}$ the ligands are:

Both ${\rm{N}}{{\rm{H}}_3}{\rm{\;and\;C}}{{\rm{l}}^ - }$

${\rm{Cr}},{\rm{\;N}}{{\rm{H}}_3},{\rm{\;C}}{{\rm{l}}^ - }$

NEET UG CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

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\mathrm{Cr}{\left( {\mathrm{N}{\mathrm{H}_3}} \right)_4}\mathrm{C}{\mathrm{l}_2}]\mathrm{Cl}

the ligands are:

View answer and explanation

Correct option: C

Both

\mathrm{N}{\mathrm{H}_3}\mathrm{\;and\;C}{\mathrm{l}^ - }

Option B (Chelates) is correct because complexes formed with bidentate or polydentate ligands are called chelates.

Practice All Chapter MCQs →

\left[ {\mathrm{PtC}{\mathrm{l}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{B}{\mathrm{r}_2}\mathrm{\;and\;}\left[ {\mathrm{PtB}{\mathrm{r}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{C}{\mathrm{l}_2}\mathrm{\;}

\left[\mathrm{Cr}(\mathrm{Ox})_{2} \mathrm{ClBr}\right]^{3-}

\text{ox =}

x

{\left[ {\mathrm{Ni}{{\left( {\mathrm{CN}} \right)}_4}} \right]^x}

\mathrm{M}{\mathrm{n}^{2 + }}

\mathrm{CuS}{\mathrm{O}_4}

{\mathrm{K}_2}\left[ {\mathrm{Ni}{{\left( {\mathrm{CN}} \right)}_4}} \right]