NEET UG PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

1 Easy

1 of 1

Understanding +4 | -1

Two conducting spheres of radii

r_1

and

r_2

are charged to equal surface charge density. The ratio of electric fields just outside the surface is:

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Correct option: D

1: 1

The correct answer is D because the electric field just outside a charged sphere is proportional to the surface charge density, which is the same for both spheres.

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The ratio of magnitude of electric displacement (D) and electric field (E) is Gauss’s Law is valid for In hydrogen like system the ratio of coulombian force and gravitational force between an electron and a proton is in the order of: Statement-1:

\overrightarrow{{E}}

in outside velocity of a conductor depends only on the local charge density

\alpha

.
Statement-2:

\overrightarrow{{E}}

in outside vicinity of a conductor is given by

\frac{\sigma}{\varepsilon_0}

. Two charges each of 1 coulomb are at a distance 1

km

apart the force between them is

P \times 10^3

then value of

{P}

is Electric field due to point charge depends on distance

r