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JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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Gauss’s law of electricity is given by
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Correct option: A
∫E⋅dA=Qε0\int \mathrm{E} \cdot \mathrm{dA}=\frac{\mathrm{Q}}{\varepsilon_0}
Option A (∫E⋅dA=Qε0\int \mathrm{E} \cdot \mathrm{dA}=\frac{\mathrm{Q}}{\varepsilon_0}) is correct because it represents Gauss's law, relating the electric flux through a closed surface to the enclosed charge.

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