JEE MATHEMATICS MCQ: CIRCLES

1 Easy

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Analyzing +4 | -1

A circle is passing through the points

A(1,1)

and

B(1,3)

and the bisector of first and third quadrant is normal to it, then its area, in square units, is

View answer and explanation

Correct option: A

2 \pi

Option A (

2 \pi

) is correct because it is the area of the circle passing through the given points with the specified normal.

More Questions from CIRCLES

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{\left( {{\alpha ^2}{x^2} - 2\alpha \mathrm{ }x + 1} \right)^{51}},

x

\left( {\alpha ,2{\alpha ^2}} \right)

{x^2} + {y^2} = 4,

{x^2} + {y^2} - 2x + 4y - 4 = 0

{x^2} + {y^2} = {a^2}

\left( {{x_1},{y_1}} \right)

\quad \alpha, \beta

\gamma

P, Q

x^2+y^2=1

A

(-1,0)

A P, A Q

A R

G P

\cos \alpha / 2, \cos \beta / 2

\cos \gamma / 2

x+y=6

x+2 y=4

x+y=5

x-y=1

9 \pi