JEE MATHEMATICS MCQ: CIRCLES

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Application +4 | -1

The locus of the middle point of the chords of the circle

{x^2} + {y^2} = {a^2}

such that the chords pass through a given point

\left( {{x_1},{y_1}} \right)

, is

View answer and explanation

Correct option: A

{x^2} + {y^2} - x{x_1} - y{y_1} = 0

Option A (

{x^2} + {y^2} - x{x_1} - y{y_1} = 0

) is correct because it represents the locus of the midpoint of the chords passing through a given point.

More Questions from CIRCLES

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{\left( {{\alpha ^2}{x^2} - 2\alpha \mathrm{ }x + 1} \right)^{51}},

x

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{x^2} + {y^2} - 2x + 4y - 4 = 0

\quad \alpha, \beta

\gamma

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A R

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\left( {2k,3k} \right),\left( {1,0} \right),\left( {0,1} \right)

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