JEE MATHEMATICS MCQ: FUNCTIONS

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The function

f(x)=\log \left(x+\sqrt{x^2+1}\right)

, is

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Correct option: C

an odd function

Option C (an odd function) is correct because f(-x) = -f(x), satisfying the definition of an odd function.

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

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f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}