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JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

1 Medium

1 of 1

Application +4 | -1

The work done in blowing a spherical soap bubble of diameter 2 cm will be (T = 0.02 N/m)

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Correct option: A

50.2 \times {10^{ - 6}}\,J

Option A (

50.2 \times {10^{ - 6}}\,J

) is correct because it's the work done calculated using the formula for the surface energy of a soap bubble, considering it has two surfaces.

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