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JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

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Application +4 | -1

The depth of water at which air bubble of radius 0.4 mm remains in equilibrium is 

\left( {{T_{\mathrm{water}}} = 72 \times {{10}^{ - 3}}\,\,N/m} \right)

View answer and explanation

Correct option: A

3.67 cm

Option A (3.67 cm) is correct because the depth is calculated by equating the excess pressure inside the air bubble to the hydrostatic pressure:

h = \frac{{2T}}{{\rho gR}}

.

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