JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1

The range of

f\left( x \right) = \sec \left( {\frac{\pi }{4}{{\cos }^2}x} \right), - \infty < x < \infty ,

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Correct option: A

\left[ {1,\sqrt 2 } \right]

Option A ([{1,\sqrt 2 }]) is correct because it represents the range of the secant function given the restricted domain of its argument.

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