JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Easy

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Application +4 | -1

The equation of tangent to the curve

\frac{{{x^2}}}{3} - \frac{{{y^2}}}{2} = 1

, which is parallel to

y = x

, is

View answer and explanation

Correct option: A

y = x \pm 1

Option A (

y = x \pm 1

) is correct because it represents the equations of the tangents to the hyperbola that are parallel to the line y=x.

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a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z