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JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

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A water drop of diameter 2 cm is broken into 64 equal droplets. The surface tension of water is 0.075  N/m.0.075\,\,N/m. In this process the gain in surface energy will be
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Correct option: A
2.8×10−4J2.8 \times {10^{ - 4}}J
Option A (2.8×10−4J2.8 \times {10^{ - 4}}J) is correct because it is calculated by finding the change in surface area and multiplying it by the surface tension.

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