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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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Application +4 | -1
In a △ABC\triangle A B C, if A=60∘A=60^{\circ}, then bc+a+ca+b\frac{b}{c+a}+\frac{c}{a+b} is equal to
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Correct option: A
1
Option A (1) is correct because by using the Law of Cosines and simplifying, we can show that bc+a+ca+b=1\frac{b}{c+a} + \frac{c}{a+b} = 1.

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