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JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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Application +4 | -1

An electron of mass '

m

' charge '

e

' falls through a distance '

h

' metre in a uniform electric field '

E

'. Then, time of fall:

View answer and explanation

Correct option: A

{t}=\sqrt{\frac{2 {hm}}{{eE}}}

Option A (

{t}=\sqrt{\frac{2 {hm}}{{eE}}}

) is correct because the time of fall is derived from kinematics and the electrostatic force acting on the electron.

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