Skip to main content
Back to ELECTRIC FIELDS AND CHARGES

JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

1 Medium
1 of 1
Application +4 | -1
Assuming that the charge on an atom is distributed uniformly in a sphere of radius 10−10 m10^{-10} \mathrm{~m}, what will be the electric field at the surface of the gold atom? For gold, Z=79\mathrm{Z}=79.
View answer and explanation
Correct option: B
1.138×1013 NC−11.138 \times 10^{13} \mathrm{~NC}^{-1}
Option B (1.138×1013 NC−11.138 \times 10^{13} \mathrm{~NC}^{-1}) is correct because it is the electric field calculated using Coulomb's law with the given charge and radius.

More Questions from ELECTRIC FIELDS AND CHARGES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.