Skip to main content
Back to d & f- BLOCK ELEMENTS

JEE CHEMISTRY MCQ: d & f- BLOCK ELEMENTS

1 Easy
1 of 1
Understanding +4 | -1
Which product is obtained during reaction of MnO4−{MnO}_4^{-}with I−{I}^{-}in faintly alkaline condition?
View answer and explanation
Correct option: B
IO3−{IO}_3^{-}
Option B (IO3−{IO}_3^{-}) is correct because in a faintly alkaline condition, permanganate oxidizes iodide to iodate.

More Questions from d & f- BLOCK ELEMENTS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.