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JEE CHEMISTRY MCQ: d & f- BLOCK ELEMENTS

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Application +4 | -1

Which of the following in its oxidation state shows the paramagnetism?

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Correct option: A

\mathrm{Tb}(\mathrm{IV})

The correct answer is A (

\mathrm{Tb}(\mathrm{IV})

) because

\mathrm{Tb}^{4+}

has unpaired electrons in its electronic configuration, making it paramagnetic.

More Questions from d & f- BLOCK ELEMENTS

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Mercury is transported in metal containers made of: Cadmipone is a mixture of: The number of element from the following that do not belong to lanthanoids is :
Eu, Cm, Er, Tb, Yb and Lu Statement-I:

{Sm}^{3+}

{Dy}^{3+}

have same colour (yellow).

Statement-II: Both ions are having same number of unpaired electrons. The most common oxidation state of Lanthanoid
elements is +3. Which of the following is likely to
also form other oxidation state? A mixture of

\mathrm{Ti}{\mathrm{O}_2}

\mathrm{BaS}{\mathrm{O}_4}