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JEE PHYSICS MCQ: KINETIC THEORY OF GASES

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For a gas at 300 K300 \mathrm{~K} temperature energy is 300 J300 \mathrm{~J} and speed is 300 m/300 \mathrm{~m} / sec. If temperature is made 2 times of initial then find out the final energy and speed.
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Correct option: A
3002 m/sec300 \sqrt{2} \mathrm{~m} / \mathrm{sec}
Option A (3002 m/sec300 \sqrt{2} \mathrm{~m} / \mathrm{sec}) is correct because the final speed is 3002 m/sec300 \sqrt{2} \mathrm{~m} / \mathrm{sec}, calculated by using the relation between speed and temperature.

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