Skip to main content
Back to KINETIC THEORY OF GASES

JEE PHYSICS MCQ: KINETIC THEORY OF GASES

1 Medium
1 of 1
Understanding +4 | -1
If csc_s is the velocity of sound in air and cc is the rms velocity, then
View answer and explanation
Correct option: C
cs=c(γ3)1/2c_{{s}}=c\left(\frac{\gamma}{3}\right)^{1 / 2}
Option C (cs=c(γ3)1/2c_{{s}}=c(\frac{\gamma}{3})^{1 / 2}) is correct because it represents the correct relationship between the speed of sound and the RMS velocity of gas molecules.

More Questions from KINETIC THEORY OF GASES

Practice All Chapter MCQs →
Assertion: The pressure exerted by an enclosed ideal gas does not depend on the shape of the container.
Reason: The pressure of an ideal gas depends on the number moles, temperature and volume of the enclosed Four particles have velocities 1,0,2,3 m/s1,0,2,3 \mathrm{~m} / \mathrm{s}. The root mean square of the particles is (in m/s\mathrm{m} / \mathrm{s} ) The translational degrees of freedom (ft)(f_t) and rotational degrees of freedom (fr)(f_r) of CH4{CH}_4 molecule are: On any planet, the presence of atmosphere implies (Crms={C_{rms}} == root mean square velocity of molecules and Ve={V_e} = escape velocity) At a given temperature, the pressure of an ideal gas of density ρ\rho is proportional to The mean free path for a gas, with molecular diameter dd and number density nn can be expressed as (T is temperature, P is pressure of the gas and kB is Boltzmann constant)\left(T \text{ is temperature, }P \text{ is pressure of the gas and }k_B \text{ is Boltzmann constant}\right)
Type at least 2 characters or jump directly:
🩺 NEET MCQs 🔬 JEE MCQs 🎯 JEE College Predictor Study guides 📊 Dashboard
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.

Continue with Free Account →