JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy

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Application +4 | -1

\frac{\sin 70^{\circ}+\cos 40^{\circ}}{\cos 70^{\circ}+\sin 40^{\circ}}=

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Correct option: C

\sqrt{3}

Option C (

\sqrt{3}

) is correct because after converting cosine to sine and applying sum-to-product formulas, the expression simplifies to

\sqrt{3}

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\triangle A B C

C

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\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=