JEE MATHEMATICS MCQ: 2D GEOMETRY SYSTEM

1 Easy

1 of 1

Understanding +4 | -1

The locus of a point which moves so that it is always equidistant from the point

A(a, 0)

and

B(-a, 0)

View answer and explanation

Correct option: B

Perpendicular bisector of the line segment

A B

Option B (Perpendicular bisector of the line segment

A B

) is correct because the locus of points equidistant from two points is the perpendicular bisector of the line segment joining them.

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\alpha

(\alpha, 2 \alpha)

\Delta A B C

A(0,2), B(2,0)

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P

2 P A=3 P B

A

(0,0)

B

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(1, \sqrt{3}),(0,0)

(2,0)

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9 x^2-16 y^2-18 x+32 y-23

=0

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