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JEE PHYSICS MCQ: OSCILLATIONS

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Application +4 | -1

The amplitude and the time period in a SHM is

0.5 \mathrm{~cm}

and

0.4 \mathrm{~s}

, respectively. If the initial phase is

\pi / 2 \mathrm{~rad}

, then the equation of SHM will be

View answer and explanation

Correct option: D

y=0.5 \cos 5 \pi t

Option D (

y=0.5 \cos 5 \pi t

) is correct because it represents the SHM equation with the given amplitude, time period, and initial phase of

\pi/2

.

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