NEET UG CHEMISTRY MCQ: THERMODYNAMICS

1 Hard

1 of 1

Application +4 | -1

When an electric current of

0.50 \mathrm{~A}

from a

12 \mathrm{~V}

supply is passed for

\frac{1805}{6} \mathrm{sec}

through a resistance in thermal contact with water maintained at 1 atm and

373 \mathrm{~K},

it is found that

0.9 \mathrm{~g}

of water is vaporized. The molar internal energy change of water is (Take

8.314 \times 373=3100

)

View answer and explanation

Correct option: A

33 \mathrm{~kJ}

Option A (33 kJ) is correct because it involves calculating the heat supplied, then accounting for the work done during vaporization to find the change in internal energy.

More Questions from THERMODYNAMICS

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The internal energy of one mole of a gas is: An ideal gas is allowed to expand both reversibly and irreversibly in an isolated system. If

{T_i}

is the initial temperature and

{T_f}

is the final temperature, which of the following statements is correct? For which of the process, ∆S is negative? The work done by a weightless piston in causing an expansion ∆V (at constant temperature), when the opposing pressure, P is variable, is given by: Assertion :- At constant pressure of the change

\mathrm{H}_2 \mathrm{O}(\mathrm{s}) \rightarrow \mathrm{H}_2 \mathrm{O}(\mathrm{g})

work done is negative.

Reason :- During phase transition work done is always negative. For the reaction,

\mathrm{X}_2 \mathrm{O_4(l}) \longrightarrow 2 \mathrm{XO}_2(\mathrm{g}), \Delta U=2.1 \mathrm{~kcal}, \Delta S=20 \mathrm{~cal} \mathrm{~K}^{-1}

300 \mathrm{~K}

. Hence,

\Delta G