JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

Let

\mathbf{x} \in \mathbf{R}

for which

\left[x+\frac{29}{100}\right]+\left[x+\frac{30}{100}\right]+\ldots+\left[x+\frac{91}{100}\right]=\mathbf{5 4 6}

. Find

\frac{[100 \mathrm{x}]}{170}

where [.] represents G.I.F.

View answer and explanation

Correct option: A

Option A (5) is correct because solving the equation involving the greatest integer function leads to [100x]/170 = 5.

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f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

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f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}