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JEE MATHEMATICS MCQ: 2D GEOMETRY SYSTEM

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Application +4 | -1
The distance of any point P(x,y)P(x, y) from the point Q(x1,y1)Q\left(x_1, y_1\right) is given by d(P,Q)=Max{∣x−x1∣,∣y−y1∣}d(P, Q)=M a x\{| x-x_1|,| y-y_1 \mid\}. If Q(1,2)Q(1,2) and d(P,Q)=3d(P, Q)=3 then locus of PP is
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Correct option: C
a square
Option C (a square) is correct because the locus of P forms a square with sides parallel to the axes, centered at Q.

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