NEET UG CHEMISTRY MCQ: REDOX REACTIONS

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Application +4 | -1

A sample of

2.5 \mathrm{~mol}

of hydrazine

\left(\mathrm{N}_2 \mathrm{H}_4\right)

loses

25 \mathrm{~mol}

of electrons on being converted to a new compound

\mathrm{X}.

Assuming that there is no loss of nitrogen in the formation of the new compound, what is the oxidation number of nitrogen in compound

\mathrm{X}?

View answer and explanation

Correct option: C

+3

Option C (+3) is correct because the initial oxidation state of N is -2, and it loses 5 electrons per N atom, resulting in a final oxidation state of +3.

More Questions from REDOX REACTIONS

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The oxidation state of iron in sodium nitroprusside is : Titrations in which liberated

{I_2}

is estimated to carry out the volumetric estimations are known as ….titrations. It is found that V forms a double salt isomorphous with Mohr’s salt. The oxidation number of V in this compound is : For redox reaction,

\mathrm{MnO}_4^ - + {\mathrm{C}_2}\mathrm{O}_4^{2 - } + {\mathrm{H}^ + } \to \mathrm{M}{\mathrm{n}^{2 + }} + \mathrm{C}{\mathrm{O}_2} + {\mathrm{H}_2}\mathrm{O}

coefficient of reactants in balanced states are

\mathrm{MnO}_4^ -

{\mathrm{C}_2}\mathrm{O}_4^{2 - }

{\mathrm{H}^ + }

Which one of the following reaction is possible at anode? The couple having oxidised and reduced forms of a substance taking part in an oxidation or reduction half-reaction is called