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NEET UG CHEMISTRY MCQ: REDOX REACTIONS

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Which one of the following reaction is possible at anode?
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Correct option: D
Fe2+→Fe3++e−\mathrm{F}{\mathrm{e}^{2 + }} \to \mathrm{F}{\mathrm{e}^{3 + }} + {\mathrm{e}^ - }
Option D (Fe2+→Fe3++e−\mathrm{F}{\mathrm{e}^{2 + }} \to \mathrm{F}{\mathrm{e}^{3 + }} + {\mathrm{e}^ - }) is correct because oxidation (loss of electrons) occurs at the anode.

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The oxidation state of iron in sodium nitroprusside is : Titrations in which liberated I2{I_2} is estimated to carry out the volumetric estimations are known as ….titrations. It is found that V forms a double salt isomorphous with Mohr’s salt. The oxidation number of V in this compound is : For redox reaction, MnO4−+C2O42−+H+→Mn2++CO2+H2O\mathrm{MnO}_4^ - + {\mathrm{C}_2}\mathrm{O}_4^{2 - } + {\mathrm{H}^ + } \to \mathrm{M}{\mathrm{n}^{2 + }} + \mathrm{C}{\mathrm{O}_2} + {\mathrm{H}_2}\mathrm{O} coefficient of reactants in balanced states are MnO4−\mathrm{MnO}_4^ -, C2O42−{\mathrm{C}_2}\mathrm{O}_4^{2 - }, H+{\mathrm{H}^ + } The couple having oxidised and reduced forms of a substance taking part in an oxidation or reduction half-reaction is called Assertion: When Cu2S\mathrm{Cu}_2 \mathrm{S} is converted into Cu+ & SO2\mathrm{Cu}^{+} \,\&\, \mathrm{SO}_2, then equivalent weight of Cu2S\mathrm{Cu}_2 \mathrm{S} will be M/8 (M=Mol\mathrm{M} / 8\,\left(\mathrm{M}=\mathrm{Mol}\right.. wt. of Cu2S\mathrm{Cu}_2 \mathrm{S})
Reason: Cu+\mathrm{Cu}^+ is converted Cu++\mathrm{Cu}^{++}, during this one electrons is lost.
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