The volume of oxygen liberated from $15\;{\rm{mL}}$ of 20 volume ${{\rm{H}}_2}{{\rm{O}}_2}$ is

NEET UG CHEMISTRY MCQ: HYDROGEN

1 Hard

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Application +4 | -1

The volume of oxygen liberated from

15\;\mathrm{mL}

of 20 volume

{\mathrm{H}_2}{\mathrm{O}_2}

View answer and explanation

Correct option: B

300 mL

Option B (300 mL) is correct because the volume of oxygen liberated is calculated by multiplying the volume of the

H_2O_2

solution by its volume strength.

Practice All Chapter MCQs →

\mathrm{CaC}_2+\mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{Ca}(\mathrm{OH})_2+' \mathrm{X}\,'

\mathrm{Mg}_2 \mathrm{C}_3+\mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{Mg}(\mathrm{OH})_2+'\mathrm{Y}\,'

\mathrm{X}

\mathrm{Y}

{H_2}{O_2} \to 2{H^ + } + {O_2} + 2{e^ - };{E^0} = - 0.68V

{\mathrm{H}_\mathrm{2}}{\mathrm{O}_\mathrm{2}}

{\mathrm{H}_2}{\mathrm{O}_2}

{SiH}_4

AlH_3

{NH}_3