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NEET UG CHEMISTRY MCQ: HYDROGEN

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Application +4 | -1
CaC2+H2O⟶Ca(OH)2+′X ′\mathrm{CaC}_2+\mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{Ca}(\mathrm{OH})_2+' \mathrm{X}\,'

Mg2C3+H2O⟶Mg(OH)2+′Y ′\mathrm{Mg}_2 \mathrm{C}_3+\mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{Mg}(\mathrm{OH})_2+'\mathrm{Y}\,'

The products ' X\mathrm{X} ' and ' Y\mathrm{Y} ' respectively are
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Correct option: B
C2H2\mathrm{C}_2 \mathrm{H}_2 and C3H4\mathrm{C}_3 \mathrm{H}_4
Option B (C2H2\mathrm{C}_2 \mathrm{H}_2 and C3H4\mathrm{C}_3 \mathrm{H}_4) is correct because the hydrolysis of CaC2\mathrm{CaC}_2 produces acetylene (C2H2\mathrm{C}_2 \mathrm{H}_2) and the hydrolysis of Mg2C3\mathrm{Mg}_2 \mathrm{C}_3 produces propyne (C3H4\mathrm{C}_3 \mathrm{H}_4).

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